Saturday, February 27, 2010

One method to solving systems

In class on Monday, we learned how to solve system of equations. You make each equation y=mx+b or x=ky+c depending on which is easier. Then, since both equations are equal the same thing, those equations are equal. Then, solve for the coordinate. For example:
If the system was:
3x+5y=15
-x+2y=4
You could make each equation into y=mx+b or x=ky+c depending on which is easier.
3x+5y=15 -x+2y=4
3/5x+y=3 2y=x+4
y=-3/5x+3 y=1/2x+2

Now both equations equal each other.

-3/5x+3=1/2x+2
1=11/10x
10/11=x

Now you have the x coordinate, find the y by plugging in the x to the original equation .

-x+2y=4
-10/11+2y=4
2y=4 10/11
y=22/51

Now, we know the coordinate. (10/11, 22/51)

1 comment:

Nick S. said...

Couldn't figure out how to get on the Blog so I'm leaving the Daily Scribe in a comment.

Today we learned how to get a system of linear equations from a word problem. We learned what numbers are coefficients in the problem and which ones are on the other side of the equal sign.

How if you have 175 people going to a concert and tickets for members and nonmembers are different prices. The total income is $5000.

Members - $20

Nonmembers - $50

You'll have two equations, one defining the amount of people and one defining the profit.

Amount of people equation
x + y = 175

Profit equation
20x + 50y = 5000

When you solve you get

x = 125
y = 50

Nick S.